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y^2-14y=46
We move all terms to the left:
y^2-14y-(46)=0
a = 1; b = -14; c = -46;
Δ = b2-4ac
Δ = -142-4·1·(-46)
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{95}}{2*1}=\frac{14-2\sqrt{95}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{95}}{2*1}=\frac{14+2\sqrt{95}}{2} $
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